by

How many millilitres of 0.05 N HCI are required to neutralize eight grams of NaOH?
(1) 5000
(2) 4000
(3) 4500
(4) 5050

To determine the volume of 0.05 N HCl required to neutralize 8 g of NaOH, follow these steps:

Step 1: Calculate Moles of NaOH

  • Molecular weight of NaOH = 40 g/mol
  • Moles of NaOH = 8 g / 40 g/mol = 0.2 moles

Step 2: Neutralization Reaction

The balanced reaction is:

NaOH+HCl→NaCl+H2O

  • 1 mole of NaOH reacts with 1 mole of HCl
  • So, 0.2 moles of NaOH requires 0.2 moles of HCl

Step 3: Calculate Equivalent of HCl

  • Normality (N) = Molarity × Equivalent factor
  • For HCl, Normality = Molarity because it fully ionizes.
  • Milliequivalents of HCl required = milliequivalents of NaOH

Step 4: Calculate Volume of 0.05 N HCl

Using the formula:

Final Answer:

(2) 4000 mL

Leave a Comment